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Labview Error 1122

The Wait has it's Timeout set to -1 so it will not Timeout. PJM Share this post Link to post Share on other sites John Lokanis 76 The 500 club Members 76 786 posts Location:Seattle, WA Version:LabVIEW 2015 Since:1993 Posted September 20, 2008 Ed ________________________________________ From: Yen [mailto:[email protected]] Sent: Monday, May 12, 2008 1:21 PM To: Edwin Dickens Cc: [email protected] Subject: Re: Error 1 on Wait on Notification On Mon, May 12, 2008 at It works great. Source

Published (2015-05-18 06:02:00) I think this is expected behaviour. The notifier transmits the status of the Stop button to the consumer loop. Show more post info Size: 100 bytes Customize: Reply 3: Re: why do i get error 1122 at dequeue element in consumer loop when i hit stop button crossrulz replied 1 You should watch out for race conditions. http://digital.ni.com/public.nsf/allkb/10AE5BC4A92626058625780600749827

I have error logging throughout my code that shows multiple references going invalid at the same time in unrelated VIs (all of these use 'private' unnamed queues). BTW: This problem only happens in the EXE deployed to a target machine and only after running for several days. It's easy! Show more post info Size: 345 bytes Customize: Reply 7: Re: why do i get error 1122 at dequeue element in consumer loop when i hit stop button matt198717 replied 1

The LV-functions that causes the application to freeze are all inside a timed loop. The VI that get the error is running as a sub VI of the same VI that called the VI that created the queue.I think the LV engine get 'confused' and If you preview a message, you lose the attachment. Each of these functions is actually buried in several sub-VIs.

Also what thread are you running this vi in? I think the LV engine get 'confused' and screws this up. But, I have searched all the VIs and the only one where the queue is destroyed is in the cleanup VI that comes after this VI and is connected by the https://forums.ni.com/t5/LabVIEW/Release-Queue-error/td-p/203122 If you don't declare the size of the queue Labview has to constantly allocate more memory for the newly acquired data.

Remove the "wait for ms multiple" function and wire a constant to the timeout of the dequeue function 2. Members 0 1 post Posted October 16, 2008 Hi! If someone sort out the problem then plz tell me thanxs Queue.vi ‏35 KB 0 Kudos Message 3 of 11 (3,064 Views) Reply 0 Kudos Re: Release Queue error [Edited] becktho Share this post Link to post Share on other sites Aristos Queue 538 LV R&D: I write C++/# so you don't have to.

So, the launcher is not responsible for dealing with this reference. http://boardreader.com/thread/why_do_i_get_error_1122_at_dequeue_eleme_5k44X1v78d.html Since all of these VIs are part of the main VI, i don't see how it is possible that the queue reference would be automatically removed from memory. Martin Share this post Link to post Share on other sites Prev 1 2 Next Page 1 of 2 Create an account or sign in to comment You need to On the BD, wire its terminal into a property node.

I do not understand. http://robertwindows.com/labview-error/labview-error-1445.html Kafka Consumer poll() returns empty set when used inside while loop Gyms in Loop/West Loop Gyms in Loop/West Loop Mountain Capelet - no cowl collar. So, there are many many instances of this queue (all unique, supposedly) that exist within each tree of reentrant VIs. Event in 1st "While Loop" must stop 2nd "While Loop" Related threads on other sites: Kafka Consumer poll() returns empty set when used inside...

Top contributing authors: Name Posts matt198717 4 user's latest post: why do i get error 1122 at... I don't have LV here, so this is off the top of my head, but doesn't LabVIEW's producer/consumer template rely on this error to stop the consumer loop when the producer I have never done something like that before? have a peek here Are you sure your CPU is fast enough to acquire and process the data simultaneously.

Run the vi in highlighting mode and observe what's going on in the block diagram. NI App support is trying to reproduce the issue. Since all of these VIs are part of the main VI, i don't see how it is possible that the queue reference would be automatically removed from memory.

Other options include using global variables and functional global variables. ___________________Try to take over the world! 1 Kudo Message 2 of 11 (3,170 Views) Reply 1 Kudo Re: Release Queue error

I only use the shared clones mode, but none of them have a uninitialized shift register... Show more post info Size: 1,036 bytes Customize: Thread profile page for "why do i get error 1122 at dequeue element in consumer loop when i hit stop button" on The system returned: (22) Invalid argument The remote host or network may be down. not only would you have to allocate millions of queues, you'd have to have them all continuously in play in order for the refnums to ever hit up against each other.

I am trying to do a loop in C. To avoid this error, make sure that all processes or threads that reference a queue are stopped prior to releasing the queue reference. Also try declaring the size of the queue and check the queue to see if it is full before you enqueue another element. http://robertwindows.com/labview-error/labview-error-6.html How could this happen??

Share this post Link to post Share on other sites John Lokanis 76 The 500 club Members 76 786 posts Location:Seattle, WA Version:LabVIEW 2015 Since:1993 Posted August 31, 2008 QUOTE Please Contact NI for all product and support inquiries. In another whileloop I dequeue the elements.The vi works fine, but when I stop it appears two "zeros" in the Line indicator. This thread profile page shows the thread statistics for: Total Authors, Total Thread Posts, and Thread Activity Home| About Us| Submit Your Site| Update Your Site| Get Search For Your Site|

In my case, however, I don't think that is possible. Wait for write loop to finish at end of ruby read loop, on client side calls New consumer desktops, consumer all-in-ones, and c... PS: Even if your app is thousands of VIs, if you're able to share it with the AEs, they'll try to replicate the bug. Copy this control (the reference) to the subVI and have it as part of the connector pane.

Share this post Link to post Share on other sites Aristos Queue 538 LV R&D: I write C++/# so you don't have to. You may want to add some code that checks if error 1122 occurs, and if so clears the error, after you exit the bottom loop. 0 Kudos Message 2 of 5 I have been using this code for a very long time (5+ years) without having a memory overrun issue.The problem I am having now is something is killing the queue reference Ben Share this post Link to post Share on other sites John Lokanis 76 The 500 club Members 76 786 posts Location:Seattle, WA Version:LabVIEW 2015 Since:1993 Posted September 3, 2008

As you can see from the error, the 'main.vi' has been spawned from a template 422 times and the reentrant subVI that got the error is one of 34 in memory The loop does not stop, because the stop button was read at the beginning. crossrulz 2 user's latest post: why do i get error 1122 at... I don't have LV here, so this is off the top of my head, but doesn't LabVIEW's producer/consumer template rely on this error to stop the consumer loop when the producer

The dequeue node returns error 1122 and 0 (the default value for the DBL data type).